If ` x= cot theta + cos theta , y= cot theta - cos theta , " then " (x^(2)-y^(2))^(2)=`

x = tan theta + cot theta, y = cos theta - sin theta rArr

x = tan theta + cot theta, y = cos theta-sin theta rArr

If cot theta + tan theta = x and sec theta - cos theta = y then

If (a cot theta+b cos ec theta)=x and (b cot theta+a cos ec theta)=y then x^(2)-y^(2) is equal to:

If 6cot theta+2cosec theta=cot theta+5cosec theta , then cos theta is

If 6cot theta+2cos ec theta=cot theta+5coec theta then cos theta=

If x=sec theta+tan theta, y=cos ec theta-cot theta then y =

Match the following {:("parametric equation","Cartesian equation"),(" List - I"," List - II"),("1) "x cos theta + y sin theta =a",","a) "(x^(2)-y^(2))^(2)=16xy),(" "x sin theta - y cos theta = b,),("2) "x=sec theta + tan theta",","b) "xy=1),(" "y=sec theta - tan theta,),("3) "xsec theta + y tan theta =a",","c) "x^(2)-y^(2)=a^(2)-b^(2)),(" "x tan theta + y sec theta = b,),("4) "x=cot theta + cos theta",","d) "x^(2)+y^(2)=a^(2)+b^(2)),(" "y=cot theta - cos theta,):}

x=a cosec theta+b cot theta, y=a cosec theta-b cot theta . Then, ((x+y)/(a))^(2)-((x-y)/(b))^(2)=4