If `vecOA=3hati+hatj-hatk` `|vecAB|=2sqrt6` and AB has the direction ratios 1,-1,and 2 then `|OB|` is

If OA=3i+j-k,|AB|=(2)/(sqrt(6)) and AB has the direction ratios 1,-1,2 then |OB|

If vec(OA) = hati - 2hatk and vec(OB) = 3 hati - 2hatj then the direction cosines of the vectore vec(AB) are

If veca=2hati+sqrt3hatj+3hatk and vecb=3hati+2hatj-2sqrt3hatk , then : find a vector in the direction of veca that has magnitude 7 units.

Let ABCD be a parallelogram. If AB=hati+3hatj+7hatk,AD=2hati+3hatj-5hatk and p is a unit vector parallel to AC, then p is equal to a) 1/(3)(2hati+hatj+2hatk) b) 1/(3)(2hati+2hatj+2hatk) c) 1/(7)(3hati+6hatj+2hatk) d) 1/(7)(6hati+2hatj+3hatk)

Let vec(OA)=hati+3hatj-2hatk and vec(OB)=3hati+hatj-2hatk. Then vector vec(OC) biecting the angle AOB and C being a point on the line AB is

Let vecOB = hati + 2hatj + 2hatk " and" vecOA = 4hati + 2hatj + 2hatk . The distance of the point B from the straight line passing through A and parallel to the vector 2hati + 3hatj + 6hatk is

Let veca= 2 hati + 3hatj - 6hatk, vecb = 2hati - 3hatj + 6hatk and vecc = -2 hati + 3hatj + 6hatk . Let veca_(1) be the projection of veca on vecb and veca_(2) be the projection of veca_(1) on vecc . Then veca_(2) is equal to (A) 943/49 (2 hati - 3hatj - 6hatk) (B) 943/(49^(2)) (2 hati - 3hatj - 6hatk) (C) 943/49 (-2 hati + 3hatj + 6hatk) (D) 943/(49^(2)) (-2 hati + 3hatj + 6hatk)

If vec(OA)=2hati-hatj+hatk, vec(OB)=hati-3hatj-5hatk and vec(OC)=3hati-3hatj-3hatk then show that CB is perpendicular to AC.

If vec(OA)=2hati-hatj+hatk, vec(OB)=hati-3hatj-5hatk and vec(OC)=3hati-3hatj-3hatk then show that CB is perpendicular to AC.

Statement1: A component of vector vecb = 4hati + 2hatj + 3hatk in the direction perpendicular to the direction of vector veca = hati + hatj +hatk is hati - hatj Statement 2: A component of vector in the direction of veca = hati + hatj + hatk is 2hati + 2hatj + 2hatk