`|{:(x," "4,-2),(4," "x,-2),(4,-2," "x):}|=0`

|{:(x+4,2x,2x),(2x,x+4,2x),(2x,2x,x+4):}|=(5x+4)(x-4)^2

By using properties of determinants, show that |{:(x+4,2x,2x),(2x,x+4,2x),(2x,2x,x+4):}|=(5x+4)(4-x)^(2)

Solve : |(x+4, 2x,2x),(2x , x+4, 2x),(2x, 2x, x+4)| = 0

|(x+4, 2x, 2x),(2x, x +4, 2x),(2x, 2x ,x+4)| = (5x + 4)(4 - x)^(2) .

Show that |(x+4,2x,2x),(2x,x+4,2x),(2x,2x,x+4)|=(5x+4)(4-x)^(2)

By using properties of determinats. Prove that- |(x+4,2x,2x),(2x,x+4,2x),(2x,2x,x+4)| = (5x + 4) (x - 4)^2

x+4=2(-2,0,2,4)

Match the following. {:("Line, parabola"," "," ""Pole"),("I". 2x-3y+4=0,y^(2)=4x," "(a)(4,6)),("II". 2x+3y-4=0,y^(2)=4x," "(b)(2,3)),("III". x-2y+4=0,y^(2)=6x," "(c)(-2,-3)),("IV". 3x+4y-4=0,x^(2)=4y," "(d)(-3//2,-1)):}

If [[x,4,-1]][(2,1,0),(1,0,2),(0,2,4)][(x),(4),(-1)]=0 then x=