If ` (2)/(x) + (3)/(y) = 6 and (1)/(x) + (1)/(2y) = 2` then

If ( 2x )/(3) - ( y )/(2) + (1)/(6)= 0 and (x)/(2) + ( 2y )/(3) = 3 then

Solve for x and y(3)/(x)+(2)/(y)=6 and (1)/(y)-(1)/(2x)=2

(5) / (x-1) + (1) / (y-2) = 2 (6) / (x-1) - (3) / (y-2) = 1

Find each of the following products: (i) (x - 4)(x - 4) (ii) (2x - 3y)(2x - 3y) (iii) ((3)/(4) x - (5)/(6) y) ((3)/(4)x - (5)/(6) y) (iv) (x - (3)/(x)) (x - (3)/(x)) (v) ((1)/(3) x^(2) - 9) ((1)/(3) x^(2) - 9) (vi) ((1)/(2) y^(2) - (1)/(3) y) ((1)/(2) y^(2) - (1)/(3) y)

solve for x and y . (5)/(x-1)+(1)/(y-2) =2 and ( 6) / ( x-1) -(3)/ (y-2) =1

{:((5)/(x - 1) + (1)/(y - 2) = 2),((6)/(x - 1) - (3)/(y - 2) = 1):}

Solve for x and y : (6)/(x-1)-(3)/(y-2)=1 (5)/(x-1)-(1)/(y-2)=2 , where x ne 1, y ne 2 .

{:(3x - 2y = 6),((x)/(3) - (y)/(6) = (1)/(2)):}