`F=6pi eta rv`, जहाँ F श्यान बल, `eta` श्यानता गुणांक, r त्रिज्या तथा v वेग है|

श्यान बल |न्यूटन का श्यानता का नियम |स्टोक का नियम तथा सीमांत वेग |स्टोक के नियम के कुछ अनुप्रयोग |द्रवों की श्यानता की निर्भरता |रेनोल्ड्स अंक |केशनली मे नियत प्रवाह |OMR|Summary

Find the dimensional formulae of the following quantities: (a) the universal gravitational constant G (b) the coefficient of viscosity eta (c) surface tension Some formula involving these quantities are F=(Gm_(1) m_(2))/(r_(2)),F=6pietarv,s=(F)/(l) where F : force, m : mass, r : distance, radius, v : speed and l : length.

Statement -1 : A tiny shere of mass m and density rho is dropped in a tall jar of glycerine of density rho_(0) . When the sphere acquires terminal velocity v, the magnitude of viscous force is mg(1 - rho_(0)//rho) . Statement -2 : Viscous force on the body falling in a medium is F =6 pi eta r v , where eta is the coeff. of viscosity of medium and r is the radius of body

In the p.m.f. of r.v. X Find a

Stoke's law states that the viscous drag force F experienced by a sphere of radius a, moving with a speed v through a fluid with coefficient of viscosity eta , is given by F=6 pi eta If this fluid is flowing through a cylindrical pipe of radius r, length l and a pressure difference of P across its two ends, then the volume of water V which flows through the pipe in time t can be written as (V)/(t)=K ((p)/(l))^(a)eta^(b)r^(c ) where k is a dimensionless constant. Correct values of a, b and c are -

The force F on a sphere of radius r moving in a medium with velocity v is given by F = 6 pi eta rv . The dimensions of eta are

The force F on a sphere of radius r moving in a medium with velocity v is given by F = 6 pi eta rv . The dimensions of eta are