A body is moving under the action of two force `vec(F_(1)=2hati-5hatj` , `vec(F_(2)=3hati-4hatj` . Its velocity will become uniform under a third force `vec(F_(3)` given by.

A body is moving under the action of two force vec(F_(1))=2hati-5hatj , vec(F_(2))=3hati-4hatj . It's velocity will become uniform under a third force vec(F_(3) given by.

A body is at rest under the action of three forces, two of which are vec(F)_(1)= 4hat(i), vec(F)_(2)= 6hat(j) , the third force is

A body is at rest under the action of three forces, two of which are vec(F)_(1)= 4hat(i), vec(F)_(2)= 6hat(j) , the third force is

A body is at rest under the action of three forces, two of which are vecF_(1)=4hati, vecF_(2)=6hatj , the third force is

If vec(OP_1)=4hati+3hatj and vec(OP_2)=8hati-5hatj find vec(p_1p_2)

The component of vec(A)=hati+hatj+5hatk perpendicular to vec(B)=3hati+4hatj is

The component of vec(A)=hati+hatj+5hatk perpendicular to vec(B)=3hati+4hatj is

A body of mass 5 kg under the action of constant force vec(F)=F_(x)hati+F_(y)hatj has velocity at t=0 s as vecv=(6hati-2hatj) m/s and at t=10s as vecv=+6hatj m/s. The force vecF is:

A body, under the action of a force vec(F)=6hati -8hatj+10hatk , acquires an acceleration of 1ms^(-2) . The mass of this body must be.

A body, under the action of a force vec(F)=6hati -8hatj+10hatk , acquires an acceleration of 1ms^(-2) . The mass of this body must be.