The velocity of a freely falling body is a function of the distance fallen through (h) and acceleration due to gravity g . Show by the method of dimensions that `v = Ksqrt(gh)` .

The velocity of a freely falling body changes as g^ph^q where g is acceleration due to gravity and h is the height. The values of p and q are

The velocity of a freely falling body changes as g^ph^q where g is acceleration due to gravity and h is the height. The values of p and q are

The average velocity of a freely falling body is numerically equal to half of the acceleration due to gravity. The velocity of the body as it reaches the ground is

The velocity of water wave v may depend on their wavelength lambda , the density of water rho and the acceleration due to gravity g . The method of dimensions gives the relation between these quantities as

The velocity of water wave v may depend on their wavelength lambda , the density of water rho and the acceleration due to gravity g . The method of dimensions gives the relation between these quantities as

Assertion : The time period of a freely falling pendulum is infinite. Reason : The effective value of acceleration due to gravity becomes zero.

A body falls freely from a height a'h' after two seconds if acceleration due to gravity is reversed the body

The uniform acceleration produced in a freely falling body due to gravitational pull of the earth is known as acceleration due to gravity. What is the value of g at the centre of earth?

Show that acceleration due to gravity at height h above the Earth’s surface is g_h = g ((R )/(R+h))^2