A particle is projected form ground with velocity u ar angle `theta` from horizontal. Match the following two columns.

A particle is projected from the ground with velocity u at angle theta with horizontal.The horizontal range,maximum height and time of flight are R,H and T respectively.Now keeping u as fixed, theta is varied from 30^(@) to 60^(@) .Then

A particle is projected from the ground with velocity u making an angle theta with the horizontal. At half of its maximum heights,

A particle is projected from ground with speed u and at an angle theta with horizontal. If at maximum height from ground, the speed of particle is 1//2 times of its initial velocity of projection, then find its maximum height attained.

A particle is projected from ground with speed u and at an angle theta with horizontal. If at maximum height from ground, the speed of particle is 1//2 times of its initial velocity of projection, then find its maximum height attained.