r(6i-3j+2i)=4

Find the distance of a point (2,5,-3) from the planer r.(6i-3j+2k)=4

The vector equation of the plane through the point (2,1,-1) and parallel to the plane r.(i+3j-k)=0 is a) r.(i+9j+11k)=6 b) r.(i-9j+11k)=4 c) r.(i+3j-k)=6 d) r.(i+3j-k)=4

the dist of two points -i+2j+6k from st line passes through 2i+3j+4k and parallel to vector 6i+3j-4k is

The angle between the planes r. (2i - j + 2k) = 3 and r. (3i - 6j + 2k) = 4

The shortest distance between the lines r=(4i-j)+lambda(i+2j-3k) and r=(i-j+2k)+mu(2i+4j-5k) is