" (d) "cot(A)/(2)+cot(B)/(2)+cot(C)/(2)=(s^(2))/(Delta)

Prove that cot.(A)/(2)+cot.(B)/(2)+cot.(C)/(2)=(s^(2))/(Delta)

With usual notations prove that in a triangle ABC, cot(A/2)+cot(B/2)+cot(C/2)=s^2/Delta

In Delta ABC , if a=3 , b=4,c=6 then ("cot" (A)/(2)+"cot" (B)/(2)+ "cot" ( C)/(2))/("cot" A + "cot" B + "cot" C)=

In Delta ABC, cot ""(A)/(2) +cot""(B)/(2) + cot""(C)/(2)=

In any Delta ABC, prove that cot((A)/(2))+cot((B)/(2))+cot((C)/(2))=(a+b+c)/(b+c-a)cot((A)/(2))

Show that cot ""(A)/(2) + cot "" ( B)/(2) + cot "" ( C ) /(2) = (S^(2))/( Delta )

In a triangle ABC,prove that (cot((A)/(2))+cot((B)/(2))+cot((C)/(2)))/(cot A+cot B+cot(C))=((a+b+c)^(2))/(a^(2)+b^(2)+c^(2))

( cot ""(A)/(2) + cot ""(B)/(2)+ cot ""( C )/( 2))/( cot A + cot B + cot C ) =