5" ) "16(x+y)^(2)-36(x-y)^(2)

Factorise: 25(x+y)^(2)- 36 (x-2y)^(2).

The centre of the hyperbola 9x^(2)-36x-16y^(2)+96y-252=0 , are

The centre of the hyperbola 9x^(2)-36x-16y^(2)+96y-252=0 , are

{:("Column" A ,, "Column" B), ((3x^(2) - 5)- (2x^(2) - 5 + y^(2)) ,, (a) x^(2) + xy + y^(2)) , (9x^(2) - 16y^(2) ,, (b) 2) , ((x^(3) - y^(3))/(x-y) ,, (c) (9x + 16y) (9x - 16y)) , ("The degree of " (x + 2) (x+3) ,, (d) x^(2) - y^(2)) , (,, (e) 1) , (,, (f) (3x + 4y) (3x - 4y)):}

Find the co-ordinates of the vertices, the foci, the eccentricity and the length of latus-rectum of the hyperbolas : (a) (x^(2))/(9) -(y^(2))/(16) = 1 (b) (i) 16x^(2) - 9y^(2) = 576 (ii) y^(2) -16x^(2) = 1 (iii) 5y^(2) - 9x^(2) = 36 (iv) 49y^(2) - 16x^(2) = 784 .

Factorize each of the following algebraic expressions: a^(2)+14a+48(2)x^(2)-4x-21y^(2)+5y-36(4)(a^(2)-5a)^(2)-36(a+7)(a-10)+16

The eccentricity of the ellipse (x^(2))/(36)+ (y^(2))/(16)=1 is

The eccentricity to the ellipse (x^(2))/(36)+(y^(2))/(16)=1 is