" (tii) "f(x)={[k(x^(2)-2x),," if "x<0],[cos x,," if "x>=0]quad " at "x=0

Find the value of k, such that the function f(x) = {(k(x^2-2x), if x = 0):} at x=0 is continuous.

For what value of k, the function f(x)={((tan2x)/(x)", if "x!=0),(k", if "x=0):} is continuous at x=0 ?

If f(x) is continuous at x=0 , where f(x)={:{(k(x^(2)-2)", for " x le 0),(4x+1", for " x gt 0):} , then k=

Let for k>0 f(x)=[(k^(x)+k^(-x)-2)/(x^(2)) if x>0] , [3ell n(k-x)-2" if ",x<=0] , if f(x) is continuous at x=0 , then k is equal to

For what value of k is the function f(x)={(sin2x)/(x),quad x!=0k,quad x=0 continuous at x=0?

If f(x) is continuous at x=0 , where f(x) = {:{((x cos x+3tan x)/(x^(2)+sin x) ", for " x !=0),(k^(2) ", for " x=0):} , then k=

If f(x)=log(sec^(2)x)^(cot^2x) for xne0 and k for x=0 is continuous at x=0 , then k is

If f(x) is continuous at x=0 , where f(x)={:{((1-cos k x)/(x^(2))", for " x!=0),(1/2 ", for " x=0):} , then k=

If f(x) is continuous at x=0 , where f(x)={:{((1-cos k x)/(x^(2))", for " x!=0),(1/2 ", for " x=0):} , then k=