If `alphaa n dbeta` are the eccentric angles of the extremities of a focal chord of an ellipse, then prove that the eccentricity of the ellipse is `(sinalpha+sinbeta)/("sin"(alpha+beta))`

If alpha, beta are the eccentric angles of the extermities of a focal chord of an ellipse, then eccentricity of the ellipse is

If alpha,beta are the eccentric angles of the extremities of a focal chord of the ellipse x^(2)/16 + y^(2)/9 = 1 , then tan (alpha/2) tan(beta/2) =

If a latus rectum of an ellipse subtends a right angle at the centre of the ellipse,then write the eccentricity of the ellipse.

If theta_(1),theta_(2) are the eccentric angles of the extremities of a focal chord of the ellipse (x^(2))/(a^(2))+(y^(2))/(b^(2))=1(a

In an ellipse,if the lines joining focus to the extremities of the minor axis form an equilateral triangle with the minor axis,then the eccentricity of the ellipse is

If the lines joining the foci of an ellipse to an end of its minor axis are at right angles , then the eccentricity of the ellipse is e =

IF alpha , beta are eccentric angles of end points of a focal chord of the ellipse x^(2)/a^(2) + y^(2)/b^(2) =1 then tan(alpha /2) tan (beta/2) is equal to

If the tangent at any point of the ellipse (x^(2))/(a^(3))+(y^(2))/(b^(2))=1 makes an angle alpha with the major axis and angle beta with the focal radius of the point of contact,then show that the eccentricity of the ellipse is given by e=cos(beta)/(cos alpha)