Home
Class 10
MATHS
If one root of x^2 +px+1=0 is the cube o...

If one root of `x^2 +px+1=0` is the cube of the other root,then p is

Promotional Banner

Similar Questions

Explore conceptually related problems

if one root of x^2+px+1=0 is square of the other, then p=

If one root of x^2+px+1=0 is square that of the other thenp=

If one root of x^2+px+1=0 is square that of the other thenp=

If one root of x^(2)+px+q=0 may be the square pf the other, then p^(3)+q^(2)+q =

If one root of x^(2)+px+q=0 may be the square pf the other, then p^(3)+q^(2)+q =

If one root of the equation x^2+px+q=0 is the square of the other then

IF one root of the equation px^2+qx+r=0 is the cube of the other, prove that , rp(r+p)^2=(q^2-2rp)^2 .

If one root of the equation x^(2) + px + q = 0 is square of the other root, then :

If one real root of the quadratic equation 81x^2 + kx + 256=0 is cube of the other root, then a value of k is