Find the normal to the ellipse `(x^2)/(18)+(y^2)/8=1` at point (3, 2).

If the normal to the ellipse " (x^(2))/(18)+(y^(2))/(8)=1 " at point (3,2)" is "ax-by-c=0" .(where "gcd(a,b,c)=1)" .Then the value of a+b+c=?

If the normal to the ellipse (x)/(18)+(y)/(8)=1 at point (3,2) is ax-by-c=0 .(where gcd(a,b,c)=1) .Then the value of a+b+c ?

Find the equation of tangent line to the ellipse (x^(2))/(8)+(y^(2))/(2)=1 at point (2,1)

The equation of normal to the ellipse 4x^(2)+9y^(2)=72 at point (3,2) is:

Show that the equation of the normal to the ellipse (x^(2))/(25)+(y^(2))/(9)=1 at ((5)/(sqrt(2)),(3)/(sqrt(2))) is the line 5x-3y=8sqrt(2)

Find the equation of the normal to the ellipse (x^(2))/(a^(2))+(y^(2))/(b^(2))=1 at the positive end of the latus rectum.

Area of the triangle formed by the x axis,the tangent and normal at (3,2) to the ellipse (x^(2))/(18)+(y^(2))/(8)=1 is

If the normal to the ellipse 3x^(2)+4y^(2)=12 at a point P on it is parallel to the line , 2x+y=4 and the tangent to the ellipse at P passes through Q (4,4) then Pq is equal to

Find the points on the ellipse (x^(2))/(4)+(y^(2))/(9)=1 on which the normals are parallel to the line 2x-y=1.