The vertex A of `DeltaABC` is (3,-1). The equation of median BE and angle bisector CF are x-4y+10=0 and 6x+10y-59=0, respectively. Equation of AC is

The vertex C of a triangle ABC is (4,-1) . The equation of altitude AD and Median AE are 2x-3y+12=0 and 2x+3y=0 respectively then slope of side AB is :

Find the equation of acute angled bisector of lines : 3x-4y+7=0and12x-5y-8=0

In Delta ABC equation of the right bisectors of the sides Ab and AC are x+y = 0 and x - y = 0 respectively .If A = (5,7) then equation of side BC is

Equation of angle bisector of the lines 3x-4y+1=0 and 12x+5y-3=0 containing the point (1,2)

In a triangle ABC , if the equation of sides AB,BC and CA are 2x- y + 4 = 0 , x - 2y - 1 = 0 and x + 3y - 3 = 0 respectively , The equation of external bisector of angle B is

In a triangle ABC , if the equation of sides AB,BC and CA are 2x- y + 4 = 0 , x - 2y - 1 = 0 and x + 3y - 3 = 0 respectively , The equation of external bisector of angle B is

The equation of the bisector of the acute angle between the lines 2x-y+4=0 and x-2y=1 is

The equations of perpendicular bisectors of the sides AB and AC of a DeltaABC are x - y + 5 = 0 and x+2y = 0 , respectively. If the point A is (1, - 2) the equation of the line BC is

Find the equation of the sides of a triangle ABC with A(1,3) as a vertex and x-2y+1=0 and y-1=0 as the equation of two of its medians.