If `f,g:R to R` are defined `f(x) = {(0 if , x in Q),(1 if, x in Q):}, g(x) = {(-1 if , x in Q),(1 if, x !in Q):}`
then find `(fog)(pi)+(gof)(e )`.

If f,g:R to R are defined f(x) = {(0 if , x in Q),(1 if, x in Q):}, g(x) = {(-1 if , x in Q),(0 if, x !in Q):} then find (fog)(pi)+(gof)(e ) .

Let f(x)= {(1, x in Q), (0, x in R-Q):} and g(x)= {(1, x in R-Q), (0, x in Q):} , find (f+g)(x) and (fg)(x).

Two functions f:R to R and g:Rto R are defined as follows: f(x)={{:(,0,x in Q),(,1,x ne Q):},g(x)={{:(,-1,x in Q),(,0,x in Q):} Then, fof (e)+fog (pi)

Two functions f:R to R and g:Rto R are defined as follows: f(x)={{:(,0,x in Q),(,1,x ne Q):},g(x)={{:(,-1,x in Q),(,0,x in Q):} Then, fof (e)+fog (pi)

If f : R to R , g : R to R are defined by f (x) = 4x - 1 and g (x) = x ^(2) + 2 then find (gof) (x)

If f: R->R be defined as follows: f(x)={1,\ if\ x in Q-1,\ if\ x !in Q Find: range of fdot

If f: R->R be defined as follows: f(x)={1,\ if\ x in Q-1,\ if\ x !in Q Find: range of fdot

IF f:R to R,g:R to R are defined by f(x)=3x-1 and g(x)=x^2+1 , then find (fog)(2)

If f:R to R , g:R to R are defined by f(x) = 3x-1 and g(x) = x^(2) + 1 then find (fog)(2) .