Find the equation of a chord of the ellipse `(x^2)/(25)+(y^2)/(16)=1` joining two points `P(pi/4)` and `Q((5pi)/4)`

Find the equation of chord of an ellipse (x^(2))/(25)+(y^(2))/(16)=1 joining two points P((pi)/(3))and Q ((pi)/(6))

If the equation of chord ofthe ellipse " (x^(2))/(25)+(y^(2))/(16)=1 " joining "],[" the two points " P((pi)/(3)) " and Q((pi)/(6)) " on it is " (x)/(lambda_(1)) + (y)/(lambda_(2)) = (sqrt(3)+1)/(2) ],[" then " 20 lambda_(1) + 25 lambda_(2) ="

Find the length of the chord of the ellipse (x^(2))/(25)+(y^(2))/(16)=1, whose middle point is ((1)/(2),(2)/(5))

Find the length of the chord x-2y-2=0 of the ellipse 4x^(2)+16y^(2)=64

The mid point of the chord 16x+9y=25 to the ellipse (x^(2))/(9)+(y^(2))/(16)=1 is

The equation of the chord of the ellipse x^(2) + 4y^(2) = 4 having the middle point at (-2, (1)/(2)) is

The equation of the chord of the ellipse 2x^(2)+5y^(2)=20 which is bisected at the point (2,1) is

The length of the chord of the ellipse (x^(2))/(25)+(y^(2))/(16)=1 ,whose mid point is (1,(2)/(5)) ,is equal to :