If x and y are connected parametrically by the equations given, without eliminating the parameter, Find `(dy)/(dx)`.
`x=asectheta, y=btantheta`

If x and y are connected parametrically by the equations given, without eliminating the parameter, Find (dy)/(dx) . x=acostheta, y=bcostheta

If x and y are connected parametrically by the equations given,without eliminating the parameter,Find (dy)/(dx)x=a sec theta,y=b tan theta

If x and y are connected parametrically by the equations given,without eliminating the parameter,Find (dy)/(dx)x=sin t,y=cos2t

If x and y are connected parametrically by the equations given, without eliminating the parameter, Find (dy)/(dx) . x=a(costheta+thetasintheta), y=a(sintheta-thetacostheta)

If x and y are connected parametrically by the equations given, without eliminating the parameter, Find (dy)/(dx) . x=sint , y=cos2t

If x and y are connected parametrically by the equations given, without eliminating the parameter, Find (dy)/(dx) . x=4t , y=4/t

If x and y are connected parametrically by the equations given, without eliminating the parameter, Find (dy)/(dx) . x=2a t^2, y=a t^4

If x and y are connected parametrically by the equations given,without eliminating the parameter,Find (dy)/(dx)x=4t,y=(4)/(t)

If x and y are connected parametrically by the equations given,without eliminating the parameter,Find (dy)/(dx)x=a cos theta,y=b cos theta

If x and y are connected parametrically by the equations given in, without eliminating the parameter, find dy/dx . x=asect,y=btant .