Home
Class 11
MATHS
The locus of the point which divides the...

The locus of the point which divides the double ordinates of the ellipse `(x^2)/(a^2)+(y^2)/(b^2)=1` in the ratio `1:2` internally is `(x^2)/(a^2)+(9y^2)/(b^2)=1` (b) `(x^2)/(a^2)+(9y^2)/(b^2)=1/9` `(9x^2)/(a^2)+(9y^2)/(b^2)=1` (d) none of these

Promotional Banner

Similar Questions

Explore conceptually related problems

The coordinates of a focus of the ellipse 4x^(2) + 9y^(2) =1 are

The locus of the poles of tangents to the director circle of the ellipse x^(2)/a^(2) + y^(2)/b^(2) = 1 with respect to the ellipse x^(2)/a^(2) + y^(2)/b^(2) = 1 is

For the ellipse (x^(2))/(a^(2))+(y^(2))/(b^(2)) =1 and (x^(2))/(b^(2))+(y^(2))/(a^(2)) =1

The locus of the point of intersection of perpendicular tangents to the ellipse (x - 1)^2/16 + (y-2)^2/9= 1 is

The line y=2t^2 meets the ellipse (x^2)/(9)+(y^2)/(4)=1 in real points if

What is the area of the ellipse 4x^(2) + 9y^(2) = 1 .

Find the locus of the mid-point of the chord of the ellipse (x^(2))/(16) + (y ^(2))/(9) =1, which is a normal to the ellipse (x ^(2))/(9) + (y ^(2))/(4) =1.

The locus of point intersection of perpendicular tangents of ellipse ((x-1)^(2))/(16)+((y-1)^(2))/(9)=1 is

The mid point of the chord 16x+9y=25 to the ellipse (x^(2))/(9)+(y^(2))/(16)=1 is