Gamma Decay

Staements I: ._zX^4 undergoes 2 alpha -decays, 2 beta -decays (negative beta ) and 2 gamma -decays. As a result, the daughter product is ._z._-2X^(A-B) . Staements II: In alpha -decay, the mass number decreases by 4 unit and atomic number decreases by 2 unit. In beta -decay (negative beta ), the mass number remains unchanged and atomic number increases by 1 unit. In gamma -decay, mass number and atomic number remain unchanged.

Staements I: ._zX^4 undergoes 2 alpha -decays, 2 beta -decays (negative beta ) and 2 gamma -decays. As a result, the daughter product is ._z._-2X^(A-B) . Staements II: In alpha -decay, the mass number decreases by 4 unit and atomic number decreases by 2 unit. In beta -decay (negative beta ), the mass number remains unchanged and atomic number increases by 1 unit. In gamma -decay, mass number and atomic number remain unchanged.

Staements I: ._zX^4 undergoes 2 alpha -decays, 2 beta -decays (negative beta ) and 2 gamma -decays. As a result, the daughter product is ._z-2X^(A-B) . Staements II: In beta -decay, the mass number decreases by 4 unit and atomic number decreases by 2 unit. In beta -decay (negative beta ), the mass number remains unchanged and atomic number increases by 1 unit. In gamma -decay, mass number and atomic number remain unchanged.

Staements I: ._zX^4 undergoes 2 alpha -decays, 2 beta -decays (negative beta ) and 2 gamma -decays. As a result, the daughter product is _(z-2)X^(A-8) . Staements II: In beta -decay, the mass number decreases by 4 unit and atomic number decreases by 2 unit. In beta -decay (negative beta ), the mass number remains unchanged and atomic number increases by 1 unit. In gamma -decay, mass number and atomic number remain unchanged.

In a gamma decay process, the internal energy of a nucleus of mass M decreases, a gamma photon of energy E and linear momentum E/c is emitted and the nucleus recoils. Find the decrease in internal energy.

In a gamma decay process, the internal energy of a nucleus of mass M decreases, a gamma photon of energy E and linear momentum E/c is emitted and the nucleus recoils. Find the decrease in internal energy.

Calculate the kinetic energy of beta -particles and the radiation frequencies corresponding to the gamma -decays shown in figure. Given, mass of ._12Mg^27 atom =26.991425 amu and mass of ._13Al^27 atom = 26.990080 amu

Calculate the kinetic energy of beta -particles and the radiation frequencies corresponding to the gamma -decays shown in figure. Given, mass of ._12Mg^27 atom =26.991425 amu and mass of ._13Al^27 atom = 26.990080 amu