A straight wore of mass 2 gram and length 50 cm is kept horizontal in a uniform magnetic field on induction `2xx 10^(-2)Wb//m^(2).` The field is horizontal and is perpendicular to the length of the wire. How much current should be passed through wire, so to balance its weight ?
`(g=10m//s^(2))`

A straight wire of lengt 2m is kept horizontla in a uniform magnetic field of induction 4xx10^(-3)Wb//m^(2). The field is horizontal and is at right angles to the length of the conductor. It is found that the conductor remains balanced, if a current of 4.9 A is passed through the conductor. What is the mass of the wire ?

A straight wire of length 0.5 metre and carrying a current of 1.2 ampere is placed in uniform magnetic field of induction 2 tesla. The magnetic field is perpendicular to the length of the wire. Find the force on the wire is

A straight wire of length 0.5 m carrying a current of 1.6 ampere is placed in a uniform magnetic field of induction 2 T. If the magnetic field is perendicular to the length of the wire, then force on the wire is

A straight wire of length 0.5 m carrying a current of 1.6 ampere is placed in a uniform magnetic field of induction 2 T. If the magnetic field is perendicular to the length of the wire, then force on the wire is

A straight wire of length 1 m, and carrying a current of 1.8 A, is placed in a uniform magnetic field of induction 2T. If the magntic field is perpendicular to the length of the wire, then the force acting on the wire is

A straight wire of length 0.5 metre and carrying a current of 1.2 ampere is placed in a uniform magnetic field of induction 2 tesla. If the magnetic field is perpendicular to the length of the wire , the force acting on the wire is

A straight wire of length 0.5 metre and carrying a current of 1.2 ampere is placed in a uniform magnetic field of induction 2 tesla. If the magnetic field is perpendicular to the length of the wire , the force acting on the wire is

A straight wire of length 0.5 metre and carrying a current of 1.2 ampere is placed in a uniform magnetic field of induction 2 tesla. If the magnetic field is perpendicular to the length of the wire , the force acting on the wire is

A conducting rod of mass 1 kg and length 1 m is suspended by two strings, so as to remain horizontal. If 2T horizontal magnetic field is applied perpendicular to the length of the rod then what amount of current should be passed through this rod to remove tension in two strings ? (Take g = 10ms^(-2) )

A straight wire of mass 200 g and length 1.5 m carries a current of 2 A. It is suspend in mid-air by a uniform horizontal magnetic field B (Figure). What is the magnitude of the magnetic field ?