Dual of (x +y)`(x'*1)` is

Dual of (x vv y) ^^ (x' vv 1) is

Dual of (x vv y) ^^ (x vv 1) = x vv x ^^ y vv y is

Dual of (x'vvy')'=x^^y is

Dual of x ^^(y vv x)=x is

Dual of (x'^^y')=xvvy is

Dual of x*(y+x) = x is

If graph of y=(x-1)(x-2) is then draw the graph of the following (i) y=|(x-1)(x-2)| (ii) |y|=(x-1)(x-2) (iii) y=(|x|-1)(|x|-2) (iv) |(|x|-1)(|x|-2)| (v) |y|=|(|x|-1)(|x|-2)|

When simplified (x^(-1)+y^(-1))^(-1) is equal to (a)\ x y (b) x+y (c) (x y)/(x+y) (d) (x+y)/(x y)

The point whose coordinates are x=x_(1)+t(x_(2)-x_(1)), y=y_(1)+t(y_(2)-y_(1)) divides the join of (x, y) and (x_(2), y_(2)) in the ratio

Find the value of (x+y) ,if (x+(y^(3))/(x^(2)))^(-1)-((x^(2))/(y)+(y^(2))/(x))^(-1)+((x^(3))/(y^(2))+y)^(-1)=(1)/(3)