Silicon forms a compound with chlorine in which 5.6 g of silicon is combined with 21.3 og chlorine. Calculate the empirical formula of the compound (Atomic mass : `Si = 28 , Cl = 35.5`)

Silicon forms a compound with chlorine in which 5.6 g of silicon is combined with 21.3 g of chlorine .Calculate the formula of the compound . ( atomic mass Si = 28 : Cl = 35-5).

Silicon (Si = 28) forms a compound with chlorine (Cl = 35.5) in which 5.6 g of silicon is combined with 21.3 g of chlorine. Calculate the empirical formula of the compound. [Hint. Total mass of silicon and chlorine in the compound = 5.6 + 21.3 = 26.9 % age of Si =(5.6)/(26.9)xx100 and %age of Cl =(21.3)/(26.9)xx100

A compound on decomposition in the laboratory produces 24.5 g of nitrogen and 70 g of oxygen. Calculate the empirical formula of the compound.

A compound of aluminium and chlorine is compsed of 9.0g Al for every 35.5g of chlorine. The emprical formula of the compound is:

4 g of copper chloride on analysis was founded to contain 1.890 g of copper (Cu) and 2.110 g of chlorine (Cl). What is the empirical formula of copper chloride? [At. Mass of Cu= 63.5 u, Cl = 35.5 u].

60 g of a compound on analy6sis produced 24 g C , 4g H , and 32 g O . The empirical formula of the compound is