The time of flight of a projectile is 10 s and range is 500m. Maximum height attained by it is [`g=10 m//s^(2)`]

A stone is projected in air. Its time of flight is 3s and range is 150m. Maximum height reached by the stone is (Take, g = 10 ms^(-2))

A stone is projected in air. Its time of flight is 3s and range is 150m. Maximum height reached by the stone is (Take, g = 10 ms^(-2))

Range of a projectile with time of flight 10 s and maximum height 100 m is : (g= -10 m//s ^2)

Range of a projectile with time of flight 10 s and maximum height 100 m is : (g= -10 m//s ^2)

A particle is thrown vertically upwards its velocity at half of the height is 10 m/s then the maximum height attained by it is ( g= 10 m//s^2)

The maximum horizontal range of a projectile is 400 m . The maximum value of height attained by it will be

A particle is thrown vertically upward. Its velocity at half of the height is 10 m/s. Then the maximum height attained by it : - (g=10 m//s^2)

A particle is thrown vertically upward. Its velocity at half of the height is 10 m/s. Then the maximum height attained by it : - (g=10 m//s^2)