Home
Class 11
MATHS
A tangent to the ellipes x^2/25+y^2/16=1...

A tangent to the ellipes `x^2/25+y^2/16=1` at any points meet the line `x=0` at a point Q Let R be the image of Q in the line `y=x,` then circle whose extremities of a dameter are `Q and R` passes through a fixed point, the fixed point is

Promotional Banner

Similar Questions

Explore conceptually related problems

The point Q is the image of the P in line x+y+4=0 and R is the image of Q in line 2x-y+7=0. If P=(1,6), then the circumcentre of triangle PQR is

Tangents drawn to circle (x-1)^(2)+(y-1)^(2)=5 at point P meets the line 2x+y+6=0 at Q on the axis.Length PQ is equal to

If the tangent to the ellipse x^(2)+2y^(2)=1 at point P((1)/(sqrt(2)),(1)/(2)) meets the auxiliary circle at point R and Q, then find the points of intersection of tangents to the circle at Q and R.

If 'P' be a moving point on the ellipse (x^(2))/(25)+(y^(2))/(16)=1 in such a way that tangent at 'P' intersect x=(25)/(3) at Q then circle on PQ as diameter passes through a fixed point.Find that fixed point.

Normal to the parabola y^(2)=8x at the point P(2,4) meets the parabola again at the point Q . If C is the centre of the circle described on PQ as diameter then the coordinates of the image of point C in the line y=x are

The image of point P(alpha,beta) with respect to the line y=-x is the point Q and the image of Q with respect to the line y=x is R. Then the mid point of R is