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If tanx=ntany ,n in R^+, then the maxi...

If `tanx=ntany ,n in R^+,` then the maximum value of `sec^2(x-y)` is equal to (a)`((n+1)^2)/(2n)` (b) `((n+1)^2)/n` (c)`((n+1)^2)/2` (d) `((n+1)^2)/(4n)`

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