Find the angle between the asymptotes of the hyperbola `(x^2)/(16)-(y^2)/9=1` .

The angle between the asymptotes of the hyperbola S=0 is

The angle between the asymptotes of the hyperbola (x^(2))/(16)-(y^(2))/(9)=1 , is

The angle between the asymptotes of the hyperbola (x^2)/(a^2)-(y^2)/(b^2)=1 is

The angle between the asymptotes of the hyperbola 3x^(2)-y^(2)=3 , is

If theta is the angle between the asymptotes of the hyperbola (x^2)/(a^2)-(y^2)/(b^2)=1 with eccentricity e , then sec (theta/2) can be

The angle between the asymptotes of the hyperbola 2x^(2)-2y^(2)=9 , is

The angle between the asymptotes of the hyperbola 24x^(2)-8y^(2)=27 is

The angle between the asymptotes of the hyperbola 27x^(2)-9y^(2)=24 , is

Show that the acute angle between the asymptotes of the hyperbola (x^(2))/(a^(2))-(y^(2))/(b^(2))=1,(a^(2)>b^(2)), is 2cos^(-1)((1)/(e)) where e is the eccentricity of the hyperbola.