The distance-time formula for the motion of a particle along a straight line is `s=t^(3)-9t^(2)+24t-18`. Find when and where the velocity is zero.

A particle moves along a line by s=t^(3)-9t^(2)+24t then S is decreasing when t in

The equation of motion of a particle moving along a straight line is s=2t^(3)-9t^(2)+12t , where the units of s and t are centrimetre and second. The acceleration of the particle will be zero after

A particle moves along a line by s = t^(3) - 9t^(2) + 24t . Then S is decreasing when t in

The equation of motion of a particle moving along a straight line is s=2t^(3)-9t^(2)+12t , where the units of s and t are cm and second. The acceleration of the particle will be zero after: a) 3/2 seconds b) 2/3 seconds c) 1/2 seconds d) 2 seconds

" A particle moves along a line by "s=t^(3)-9t^(2)+24t," then "S" is decreasing when "t in

The distance s travelled by a particle moving on a straight line in time t sec is given by s=2t^(3)-9t^(2)+12t+6 then the initial velocity of the particle is

The displacement of a particle moving in a straight line is given by s=t^(3)-6t^(2)+3t+4 meters.The velocity when acceleration is zero is "