On the basis of dimensional arguments, rule out the wrong relation for Kinetic Energy. (i)`(3)/(16)m upsilon^2` (ii) `(1)/(2)m upsilon^2 + ma`

The SI unit of energy is J = kg m^2 s^(-2), that of speed upsilon is ms^(-1) and of acceleration a is ms^(-2) which of the formulae for kinetic energy (K) given below can you rule out on the basis of dimensional arguments (m stands for the mass of the body). (a) K = m^2 upsilon^3 (b) K = (1)/(2)m upsilon^2 (c ) K= ma (d) K =(3)/(16)m upsilon^2 (e ) K = (1)/(2) m upsilon^2 +ma

The SI unit of energy is J = kg m^2 s^(-2), that of speed upsilon is ms^(-1) and of acceleration a is ms^(-2) which of the formulae for kinetic energy (K) given below can you rule out on the basis of dimensional arguments (m stands for the mass of the body). (a) K = m^2 upsilon^3 (b) K = (1)/(2)m upsilon^2 (c ) K= ma (d) K =(3)/(16)m upsilon^2 (e ) K = (1)/(2) m upsilon^2 +ma

Check the dimensional consistency of the following equations : (i) upsilon = u +at (ii) s = ut +(1)/(2) at^2 (iii) upsilon^2 - u^2 = 2as

Check by the method of dimensions, whether the folllowing relation are dimensionally correct or not. (i) upsilon = sqrt(P//rho) , where upsilon is velocity. P is prerssure and rho is density. (ii) v= 2pisqrt((I)/(g)), where I is length, g is acceleration due to gravity and v is frequency.

The SI unit of energy is J=kg m^(2)s^(-2) , that of speed v is ms^(-1) and of acceleration a is ms^(-2) . What of the formulae for kinetic energy (k) given below can you rule out on the basis of dimensional arguments (m stands for the mass of the body) : (a) K = m^(2)v^(2) (b) K = (1/2)mv^(2) ("c") K= ma (d) K = (3/16)mv^(2) (e) K=(1/2)mv^(2)+ma

The SI unit of energy is J=kg m^(2)s^(-2) , that of speed v is ms^(-1) and of acceleration a is ms^(-2) . What of the formulae for kinetic energy (k) given below can you rule out on the basis of dimensional arguments (m stands for the mass of the body) : (a) K = m^(2)v^(2) (b) K = (1/2)mv^(2) ("c") K= ma (d) K = (3/16)mv^(2) (e) K=(1/2)mv^(2)+ma

The SI unit of energy is J=kg m^(2)s^(-2) , that of speed v is ms^(-1) and of acceleration a is ms^(-2) . What of the formulae for kinetic energy (k) given below can you rule out on the basis of dimensional arguments (m stands for the mass of the body) : (a) K = m^(2)v^(2) (b) K = (1/2)mv^(2) ("c") K= ma (d) K = (3/16)mv^(2) (e) K=(1/2)mv^(2)+ma

Using dimensional analysis, check the correctness of the following relations : (i) S_(nth) = u+(a)/(2) (2n-1) (ii) lambda = h//m upsilon (ii) = mc^2 where the symbole have their usual menaings.]