If the base angles of triangle are `((22)/(12))^@` and `(112 1/2)^@` , then prove that the altitude of the triangle is equal to `1/2` of its base.

If the base angles of triangle are ((22 1/2))^@ and (112 1/2)^@ , then prove that the altitude of the triangle is equal to 1/2 of its base.

If the base angles of triangle are 22 1/2a n d112 1/2 , then prove that the altitude of the triangle is equal to 1/2 of its base.

The base angle of triangle are 22 (1)/(2)^@ and 112 (1)/(2)^@ if b is the base and h is the height of the triangle , then

If the base angles of a triangle are 22(1)/(2),112(1)/(2) then third angle is

The base angles of a triangle are (22 (1)/(2))^(@)and (112 (1)/(2))^(@). If b is the base and h is the height of the triangle then-

If the base angles of a triangle are 22 (1^(0) )/(2) , 112 (1^(0))/(2) , then base and height are in the ratio

If the area of triangle with base 12 cm is equal to the area of a square with side 12 cm, then the altitude of the triangle is:

The base angle of triangle are 22 (1^(@))/(2) and 112 (1^(@))/(2). If b is the base and h is the height of the triangle, then : a) b=2h b)b=3h c) b (1 + sqrt3) h d) b = (2 + sqrt3) h