A wheel has moment of inertia `5 xx 10^(-3) kg m^(2)` and is making `20 "rev" s^(-1)`. The torque needed to stop it in `10 s` is….. `xx 10^(-2) N-m`

A wheel has a moment of inertia of 5xx10^(-3) kg m"^(2) and is making "20 rev/s". What is the magnitude of the torque required to stop it in 10 s?

A fly wheel of moment of inertia 4xx10^(-3)kgm^(2) is makign 10 revolution per second. The torque required to stop it in 5 second is:

A wheel of moment of inertia 5xx10^(-3) kg m^(2) is making 20 revolutions per second. If it is stopped in 20 s, then its angular retardation would be

A wheel of moment of inertia 2 xx 10^3 kg m^2 is rotating at uniform angular speed of 4 rad/s,.then . the torque required to stop it in one second is,

A flywheel of moment of inertia 3 xx 10^(2) kg m^(2) is rotating with uniform angular speed of 4.6 rad s^(-1) . If a torque of 6.9 xx 10^(2)Nm retards the wheel, then the time in which the wheel comes to rest is