Find the vertices of the hyperbola `9x^2-16 y^2-36 x+96 y-252=0`

The vertices of the hyperbola 9x^(2)-16y^(2)-36x+96y-252=0 are

The centre of the hyperbola 9x^(2)-36x-16y^(2)+96y-252=0 , are

Find the length of the transverse and conjugate axes, eccentricity, centre, foci and directrices of the hyperbola . 9x^2 - 16y^2 - 72x + 96y - 144 = 0

Find the eccentricity of the hyperbola 9y^(2)-4x^(2)=36

Find the coordinates of the foci,the eocentricity,the latus rectum,and the equations of directrices for the hyperbola 9x^(2)-16y^(2)-72x+96y-144=0