factorize (a) `(3a-1)^2` - 6a + 2

Factorize: (2a+1)^3+\ (a-1)^3

factorize : x^2+(1)/(x^2)-3

Factorize: (2a+1)^(3)+(a-1)^(3)

Factorize (1)/(6) a^(2) - a + (4)/(3)

(c) Factorize x^(3) -2x^(2) -5x +6

Factorize :x^(3)-6x^(2)+11x-6

Factorize: 6a b-b^2+12 a c-2b c

The factors of 8a^3+b^3-6a b+1 are (a) (2a+b-1)(4a^2+b^2+1-3a b-2a) (b) (2a-b+1)(4a^2+b^2-4a b+1-2a+b) (c) (2a+b+1)(4a^2+b^2+1-2a b-b-2a) (d) (2a-1+b)(4a^2+1-4a-b-2a b)

Look at the following pattern : (i) 28 = 2^(2) xx 7^1 , Total number of factors (2+1) (1+1)= 3 xx 2 =6 28 is divisible by 6 factors i.e., 1,2,4,7,14,28 (ii) 30=2^(1) xx 3^(1) xx 5^(1) , Total number of factors ( 1+1)(1+1)(1+1)=2 xx 2 xx 2 =8 30 is divisible by 8 factor i.e., 1,2,3,5,6,10,15,30 find pattern

Look at the following pattern : (i) 28 = 2^(2) xx 7^1 , Total number of factors (2+1) (1+1)= 3 xx 2 =6 28 is divisble by 6 factors i.e., 1,2,4,7,14,28 (ii) 30=2^(1) xx 3^(1) xx 5^(1) , Total number of factors ( 1+1)(1+1)(1+1)=2 xx 2 xx 2 =8 30 is divisble by 8 factor i.e., 1,2,3,5,6,10,15,30