Two straight lines pass through the fixed points `(+-a, 0)` and have slopes whose products is `pgt0` Show that the locus of the points of intersection of the lines is a hyperbola.

Two straight lines pass through the fixed points (+-a,0) and have slopes whose products is p>0 show that the locus of the points of intersection of the lines is a hyperbola.

Equation of straight line passing through the points (2,0) and (0, -3) is

The locus of a point equidistant from two intersecting lines is

Two straight lines having variable slopes m_(1) and m_(2) pass through the fixed points (a, 0) and (-a, 0) respectively. If m_(1)m_(2)=2 , then the eccentricity of the locus of the point of intersection of the lines is

In the xy plane,the line L_(1) passes through the point (1,1) and the line L_(2) passes through the point (-1,1). If the difference of the slopes of the lines is 2. Then the locus of the point of intersection of the lines L_(1) and L_(2) is

Graph the line passing through the point P and having slope m. P=(-1,3),m=0

Find the equation of the straight line passing through the point (6,2) and having slope -3.

A variable line passing through the point P(0, 0, 2) always makes angle 60^(@) with z-axis, intersects the plane x+y+z=1 . Find the locus of point of intersection of the line and the plane.