If a,b,c are the variance of the binomial distribution `(2//3+1//3)^(12), (3//4+1//4)^(12), (5//6+1//6)^(12)` respectively then the ascending order of a,b,c is

If a,b,c are the means of the binomial distribution (2//3+1//3)^(12), (3//4+1//4)^(12), (5//6+1//6)^(12) respective then the ascending order of a,b,c is

Arrange in ascending order: 2/3, 1/6, 5/12, 3/4

If the inverse of the matrix [(1,2),(3,-5)] is 1/11[(a,b),(c,d)] then the ascending order of a,b,c,d is

The mean and variance of a binomial distribution are 4 and 3 respectively, then the probability of getting exactly six successes in this distribution, is a. ^(16)C_6(1/4)^(10)(3/4)^6 b. ^(16)C_6(1/4)^6(3/4)^(10) c. ^(12)C_6(1/(20))^( )(3/4)^6 d. ^(12)C_6(1/4)^6(3/4)^6

If the inverse of the matrix [[1,2],[3,-5]]^(n) is 1/11[[a,b],[c,d]] , then the ascending order of a, b, c, d is

In a binomial distribution n=12, p=1//3 . Then mean and variance are

In a binomial distribution n=12, p=1//3 . Then mean and variance are

If A,B,C are the cofactors of 2,3,-5 in the matrix [(-1,0,5),(1,2,-2),(-4,-5,3)] then the ascending order of A,B,C is

The vertices of a parallelogram in order are A(1,2), B(4, y), C(x, 6) and D(3,5). Then (x, y) is