The wavelength of de - Broglie wave is `2 mu m` , then its momentum is `( h = 6.63 xx 10^(-34 J-s)`

The wavelength of de-Broglie wave is 3 mu m , then its momentum (h = 6.63 xx 10^(-34) Js) is

The de-Broglie wavelength of an electron is 600 nm . The velocity of the electron is: (h = 6.6 xx 10^(-34) J "sec", m = 9.0 xx 10^(-31) kg)

The speed of electron having de Broglie wavelength of 10 ^(10) m is ( me = 9.1 xx 10 ^(-31) kg, h = 6.63xx 10^(-34) J-s)

A dust particle of mass 2 mg is carried by wind with a velocity of 100 cm/s. What is the de-Broglie wavelength associated with the dust particle? ( h = 6.63 xx 10^(-34) J-s )

A particle having a de Broglie wavelength of 1.0 A^(0) is associated with a momentum of (given h=6.6xx10^(-34)Js )

If the mass of neutron = 1.7 xx 10^(-27) kg, then the de-Broglie wavelength of neutron of energy 3 eV is (h = 6.6 xx 10^(-34) J s)

An X ray beam has a wavelength of 0.010 Å. What is its momentum ? (h=6.63 xx10^(9-34) J-s)

A body of mass x g is moving with a velocity of 100m/s. It de Broglie wavelength is 6.62xx10^(-35)m . Hence x is (h=6.62xx10^(-34)J-s)

The momentum of a paricle which has a d-Broglie wavelength of 0.1 nm is ( h= 6.6 xx10^(-34) J s)