Let `P` be the family of parabolas `y=x^2+p x+q ,(q!=0),` whose graphs cut the axes at three points. The family of circles through these three points have a common point (1, 0) (b) (0, 1) (c) (1, 1) (d) none of these

Let P be the family of parabolas y=x^2+p x+q ,(q!=0), whose graphs cut the axes at three points. The family of circles through these three points have a common point (a) (1, 0) (b) (0, 1) (c) (1, 1) (d) none of these

Let P be the family of parabolas y=x^(2)+px+q,(q!=0), whose graphs cut the axes at three points.The family of circles through these three points have a common point (1,0)(b)(0,1)(c)(1,1)(1,1)(d) none of these

P, Q, and R are the feet of the normals drawn to a parabola ( y−3 ) ^2 =8( x−2 ) . A circle cuts the above parabola at points P, Q, R, and S . Then this circle always passes through the point. (a) ( 2, 3 ) (b) ( 3, 2 ) (c) ( 0, 3 ) (d) ( 2, 0 )

P, Q, and R are the feet of the normals drawn to a parabola ( y−3 ) ^2 =8( x−2 ) . A circle cuts the above parabola at points P, Q, R, and S . Then this circle always passes through the point. (a) ( 2, 3 ) (b) ( 3, 2 ) (c) ( 0, 3 ) (d) ( 2, 0 )

Property 4: The equation of the family of circles passing through two given points P(x_(1),y_(1)) and Q(x_(2),y_(2))

P, Q, and R are the feet of the normals drawn to a parabola ( y−3)^2=8(x−2) . A circle cuts the above parabola at points P, Q, R, and S. Then this circle always passes through the point. (a)(2, 3)(b)(3, 2)(c)(0, 3) (d) (2, 0 )

If 3a+2b+c=0 the family of straight lines ax+by+c=0 passes through the fixed point (p, q) then p + q

" The locus of the vertices of the family of parabolas " y=ax^(2)+2a^(2)x+1 " is " (a!=0) " a curve passing through the point "