Given `DeltaH` for the process `Li(g)rarrLi^(+3)(g) + 3e^(-)` is `19800kJ//"mole" & IE_(1)` for `Li` is `520` then `IE_(2) & IE_(1)` of `Li^(+)` are respectively (approx value) :-

IE_(1), IE_(2) and IE_(3) values are 100, 150 and 1500 eV respectively. The element can be

IE_(1), IE_(2) and IE_(3) values are 100, 150 and 1500 eV respectively. The element can be

IE_(2) > IE_(1) for a given element - why?

The energy needed for Li_(g) rarr Li_(g)^(3+) + 3e is 1. 96 xx 10^4 kJ mol ^(-1) . If the first ionisation energy of Li is 520 k J mol^(-1) . Calcuate the second ionisation energy of Li . (Given : IE_1 for H = 2 . 2. 18 xx 10^(-18) k J "atom"^(-1) ).

The energy needed for Li_(g) rarr Li_(g)^(3+) + 3e is 1. 96 xx 10^4 kJ mol ^(-1) . If the first ionisation energy of Li is 520 k J mol^(-1) . Calcuate the second ionisation energy of Li . (Given : IE_1 for H = 2 . 2. 18 xx 10^(-18) k J "atom"^(-1) ).