0.45 g of a dibasic acid is completely netralised with 100 ml `N/10` NaOH . The molecular weight of acid is

0.45 g of a dibasic acid is completely neutralised with 100 ml N/10 NaOH . The molecular weight of acid is

Two formulal to calculate number of milli equivalkents (mlQ) Numbr of miliequivalents =("weight")/("GEW")xx1000 Numbr of milliequivalents= volume in ml xx Normality of solution 0.09 grams of dibasic acid neutralise 40 ml of N/20 NaOH solution. Molecular weight of acid is

Two formulal to calculate number of milli equivalkents (mlQ) Numbr of miliequivalents =("weight")/("GEW")xx1000 Numbr of milliequivalents= volume in ml xx Normality of solution 0.09 grams of dibasic acid neutralise 40 ml of N/20 NaOH solution. Molecular weight of acid is

0.126g of an acid is needed to completely neutralise 20 mL 0.1 N NaOH solution. The equivalent weight of the acid is-

1.575 g of a dibasic acid is neutralised by 25 mL 1 M NaOH solution. Hence, molar mass of dibasic acid is -

0.1092 g of a dibasic acid is exactly neutralized by 21cm^(3) of 0.1N NaOH. Calculate the molecular mass of the acid.

0.104 g of a monobasic acid was just neutralised y 10 ml (N)/(20) NaOH. Molar mass of the acid is

1.25g of a solid dibasic acid is completely neutralised by 25mL of 0.25 molar Ba (OH)_2 solution. Molecular mass of the acid is :

1.25g of a solid dibasic acid is completely neutralised by 25mL of 0.25 molar Ba (OH)_2 solution. Molecular mass of the acid is :