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Bichromatic light of wavelengths lambda1...

Bichromatic light of wavelengths `lambda_1= 5000Å and lambda_2=7000Å` are used in YDSE. Then,

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Bichromatic light is used in YDSE having wavelengths lambda_1 = 400 nm and lambda_2= 700nm . Find minimum order of bright fringe of lambda_1 which overlaps with bright fringe of lambda_2 .

Bichromatic light is used in YDSE having wavelengths lambda_1 = 400 nm and lambda_2= 700nm . Find minimum order of bright fringe of lambda_1 which overlaps with bright fringe of lambda_2 .

In YDSE, if a bichromatic light having wavelengths lambda_(1) and lambda_(2) is used, then maxima due to both lights will overlaps at a certain distance y from the central maxima. Take separation between slits as d and distance between screen and slits as D. Then the value of y will be

In YDSE, if a bichromatic light having wavelengths lambda_(1) and lambda_(2) is used, then maxima due to both lights will overlaps at a certain distance y from the central maxima. Take separation between slits as d and distance between screen and slits as D. Then the value of y will be

Bichromatic light is used in YDSE having wavelengths lambda_(1)=400nm and lambda_(2)=700nm Find minimum order of lambda_(1) which overlaps with lambda_(2)

Bichromatic light is used in YDSE having wavelengths lambda_(1)=400nm and lambda_(2)=700nm Find minimum order of lambda_(1) which overlaps with lambda_(2)

In YDSE a parallel beam of incident light consists of two wavelengths lambda_(1)=4000Å and lambda_(2)=5600Å . The minimum distance y on the screen, measured from the central axis, where the bright fringe due to two wavelengths coincide is (nlambda_(1)D)/(d) . Find n.

In YDSE a parallel beam of incident light consists of two wavelengths lambda_(1)=4000Å and lambda_(2)=5600Å . The minimum distance y on the screen, measured from the central axis, where the bright fringe due to two wavelengths coincide is (nlambda_(1)D)/(d) . Find n.

The ratio of resolving power of an optical microscope for two wavelength lambda_(1)=4000Å and lambda_(2)=6000Å is: