Show that the acute angle between the asymptotes of the hyperbola `(x^2)/(a^2)-(y^2)/(b^2)=1,(a^2> b^2),` is `2cos^(-1)(1/e),` where `e` is the eccentricity of the hyperbola.

The angle between the asymptotes of the hyperbola (x^2)/(a^2)-(y^2)/(b^2)=1 is

Find the angle between the asymptotes of the hyperbola (x^(2))/(16)-(y^(2))/(9)=1

The angle between the asymptotes of the hyperbola 3x^(2)-y^(2)=3 , is

The angle between the asymptotes of the hyperbola (x^(2))/(16)-(y^(2))/(9)=1 , is

If the angle between the asymptotes of hyperbola (x^(2))/(a^(2))-(y^(2))/(b^(2))=1 id (pi)/(3) , then the eccentnricity of conjugate hyperbola is _________.

If theta is the angle between the asymptotes of the hyperbola (x^2)/(a^2)-(y^2)/(b^2)=1 with eccentricity e , then sec (theta/2) can be

The magnitude of the gradient of the tangent at an extremity of latera recta of the hyperbola (x^(2))/(a^(2))-(y^(2))/(b^(2))=1 is equal to (where e is the eccentricity of the hyperbola)