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How much of NaOH is required to neutrali...

How much of NaOH is required to neutralise 1500 `cm^(3)` of 0.1N HCl? (Na= 23)

A

4g

B

40g

C

60g

D

6g

Text Solution

Verified by Experts

The correct Answer is:
D
As, `(W)/(E.W) = (V xx N)/(1000)`
E.W (NaOH) = 40m V= 1500 `cm^(3)`,
N= 0.1 N, W= ?
`rArr W= (1500 xx 0.1 xx 40)/(1000) rArr W= 6gm`
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