The oxidation number and the electronic configuration of sulphur in `H_(2)SO_(4)` is

Options

A. `+3, 1s^(2) 2s^(2) 2p^(6) 3s^(2) 3p^(1)`
B. `+6, 1s^(2) 2s^(2) 2p^(6)`
C. `+4: 1s^(2) 2s^(2) 2p^(6) 3s^(2)`
D. `+2, 1s^(2) 2s^(2) 2p^(6) 3s^(2) 3p^(2)`

Answer

B

Explanation

Let x be the oxidation number of S in `H_(2)SO_(4)`
`2 + x -2 xx 4= 0 rArr 2 + x - 8 = 0 rArr x 6 " " :.` Oxidation No. 6,
Electronic configuration is `2s^(2) 2p^(6)`
Oxidation state = +6