A radioactive isotope having a half life of 2.3 days was received after 9.2 days. It was found that there were 300mg of the isotope in the container. The initial amount of the isotope was

Options

A. 1200mg
B. 3600mg
C. 4800 mg
D. 2400mg

Answer

C

Explanation

`t_(1//2) = (0.693)/(k) rArr k = (0.693)/(2.3) = 0.3013`
`t= (2.303)/(k) "log" (N_(0))/(N_(t)) rArr "log" (N_(0))/(N_(t)) = (kt)/(2.303)`
`rArr log N_(0) - log N_(t) = (kt)/(2.303)`
`log N_(0) = (0.3013 xx 9.2)/(2.303) + 2.4771 , N_(0) = 4800 mg`.