A body of mass 10 mg is moving with a velocity of `100 ms^(-1)`.The wavelength of de-Brogile wave associated with it would be (`h = 6.63 xx 10^(-34)` Js)

Options

A. `6.63 xx 10^(-35) m`
B. `6.63 xx 10^(-34)` m
C. `6.63 xx 10^(-31)` m
D. `6.63 xx 10^(-37)` m

Answer

C

Explanation

`m = 10 mg = 10 xx 10^(-3) g`
= `10 xx 10^(-6)` kg = `10^(-5)` kg
`v = 100 ms^(-1)`, de Brogile, `lambda = ?`
`h = 6.63 xx 10^(-34) Js^(-1)`
de Brogile relation, `lambda = (h)/(mv)`
`lambda = (6.63 xx 10^(-34)Js^(-1))/(10^(-5) xx 100) = (6.63 xx 10^(-34))/(10^(-3))`
= `6.63 xx 10^(-31)` m.