For the reaction `Fe_(2)O_(3)+3COto2Fe+3CO_(2)`, the volume of carbon monoxide required to reduce one mole of ferric oxide is

Options

A. `67.2dm^(3)`
B. `11.2dm^(3)`
C. `22.4dm^(3)`
D. `44.8dm^(3)`

Answer

A

Explanation

`{:(Fe_(2)O_(3)+3COto2Fe+3CO_(2),),(1vol." " 3vol " " 2vol . " " 3vol.,),(1mol " " 3 mol. " " 2 mol.""3mol,):}`
`(becausevol%=mol%)`.
One gram mol of any gas occupies 22.4 litre at NTP. 1 mol of `Fe_(2)O_(3)` requires 3 mol of CO for its reduction i.e., 1 mol of `Fe_(2)O_(3)`
requires `3xx22.4` litre or 67.2 `dm^(3)` CO to get itself reduced .