The calculated bond order in superoxide ion is :

Options

A. 1.5
B. 1
C. 2.5
D. 2

Answer

A

Explanation

The bond order of superoxide ion `O_(2)^(-)` is `O_(2)^(-)to sigma1s^(2)sigma^(**)1s^(2)sigma2s^(2)sigma^(**)2s^(2)sigma2p_(z)^(2)pi2p_(x)^(2)~~pi2p_(y)^(2)pi^(**)3p_(x)^(2)~~pi^(**)2p_(y)^(1)`
Bond oeder `=1//2[N_(b)-N_(a)]`
`=1//2[10-7]=1.5`