The correct set of four quantum numbers for outermost electron of potassium (Z=19 ) is

Options

A. `3,1,0,1/2`
B. `4,0,0,1/2`
C. `3,0,0,1/2`
D. `4,1,0,1/2`

Answer

B

Explanation

The electronic configuration fo K(Z=19) is `1s^(2)2s^(2)2p^(6)3s^(2)4s^(1)`.
Thus the outermos configuration is `4s^(1)`, the four quantum numbers for this `e^(-)` are
n=4,l=0,m=0 and s=1/2.