0.5 mol each of `H_(2), SO_(2)` and `CH_(4)` are ketp in a container. A hole was made in the container. After 3 hours, the order of partial pressure in the container will be `:`

Options

A. `pSO_(2)gtpCH_(4)gtpH_(2)`
B. `pH_(2)gtpSO_(2)gtpCH_(4)`
C. `pH_(2)gvtpC_(4)gtpSO_(2)`
D. `pSO_(2)gtpH_(2)gtpCH_(4)`

Answer

A

Explanation

According to Graham's law of diffusion,
rate of diffusion `prop sqrt(1/("mol. Mass))`
since equal moles of all gases were taken in the container the rate of diffusion will be in the order.
`H_(2)gtCH_(4)gtSO_(2)`
`:.` The order of partial pressure of the gases remaining in the container will be:
`P_(SO_(2))gtp_(CH_(4))gtp_(H_(2))`